Let's use W for width and L for length. The perimeter of the court can be expressed as 2W + 2L, so:
2W + 2L = 128
We can simplify this equation by dividing each term by 2 to get:
W + L = 64
We can also solve for one of the variables. Let's subtract L from both sides to solve for W:
W = 64 - L
We also know that:
6L + 9W = 444
Now we can use substitution to solve the system of equations. Plug 64 - L in for W in the second equation:
6L + 9(64 - L) = 444
Distribute the 9:
6L + 576 - 9L = 444
Combine like terms:
-3L + 576 = 444
Solve for L. First we can subtract 576 from both sides:
-3L = -132
Next, divide by -3:
L = 44 ft
Now that we know the length, we can plug it into the perimeter equation to find the width.
88 + 2W = 128
2W = 40
W = 20 ft
The answer is 20 ft wide by 44 ft long.