Question

To test the effectiveness of a gunpowder mixture, 1 gram was exploded under controlled STP conditions, and the reaction chamber was found to expand to 310 cm3. What volume would these gases occupy at the temperature produced by an uncontrolled explosion (2,200°C) and 2.1 atmospheres of pressure?

Answer 1

Given:

STP (initial) conditions where: P1 = 1 atm and T1 = 298 K

Volume of gas V1 = 310 cm3

Final conditions:

P1 = 2.1 atm

T2 = 2200 + 273 = 2473 K

To determine:

The final volume (V2) occupied by the gas

Step-by-step explanation:

Using the combined gas law relation:-

P1V1/T1 = P2V2/T2

V2 = (P1V1/T1)(T2/P2)

= (1*310/298)(2473/2.1) = 1225 cm3

Ans: The volume occupied by the gas under uncontrolled explosion is 1225 cm3

Answer 2

1,300 cm^3

Step-by-step explanation:

Hello! If you read the question carefully, apply the appropriate combined gas law formula, and solve it. As I am currently doing this lesson, my calculations arrived at the answer stated above (1,300 cm^3 ). I would add the necessary math, but it would make this answer overwhelming and a daunting task to read. Therefore, I'm keeping it short. Hope this helps you!