Question

How many particles can be stored in a 4.0 L container at room temperature (23C) and standard atmospheric pressure (101.3 kPa)

Answer 1

= 9.93*10^2^2 particles

Step-by-step explanation:

Answer 2

Answer:- There are
`9.93*10^2^2` particles in the container present at 23 degree C and 101.3 pKa.

Solution:- The given volume of the container is 4.0 L at 23 degree C and 101.3 kPa pressure.

We would calculate the moles using ideal gas law equation(PV = nRT) and then the moles are converted to particles on multiply the moles by Avogadro number.

Let's convert degree C to kelvin and pKa to atm.

T = 23 + 273 = 296 K

P = 101.3 pKa = 1 atm

R =
`0.0821((atm.L)/(mol.K))`

V = 4.0 L

n = ?

Let's plug in the values in the equation:

1(4.0) = n(0.0821)(296)

4.0 = n(24.3)

`n=(4.0)/(24.3)`

n = 0.165 mol

Let's multiply the moles by Avogadro number to get the number of particles:

`0.165mol((6.02*10^2^3 particles)/(1 mol))`

=
`9.93*10^2^2` particles

So, from above calculations there would be
`9.93*10^2^2` particles in the container.