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Can i please have help with number 6

Can i please have help with number 6-example-1
User Jageen
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1 Answer

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Length of the diameter = sqrt ( (-12- (-8)^2) +(2-0)^2) )
= sqrt (16 + 4) = sqrt20
so radius = sqrt 20 / 2 = sqrt5
so r^2 = 5


Center of the circle = coordinates of the midpoint of the diameter =

-8-12/2 , 2-0 / 2 = (-10, 1)

(x - a)^2 + (y - b)^2 = r^2 is general form of a circle so here the circle is:_

(x + 10)^2 + (y - 1)^2 = 5 Answer

Its B
User Johnny Rocket
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