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27 votes
27 votes
What function translates the function f(x) = |x| to the right 2 units and up 10 units?

g(x) = |_| +__

User Doubleplusgood
by
3.0k points

2 Answers

7 votes
7 votes
Answer:
It is called a constant function :)
not sure if this is what ur looking for but I hope it helps!
User Mak Sing
by
2.7k points
21 votes
21 votes

Answer:


g(x)=|x-2|+10

Explanation:

Translations


f(x+a) \implies f(x) \: \textsf{translated $a$ units left}


f(x-a) \implies f(x) \: \textsf{translated $a$ units right}


f(x)+a \implies f(x) \: \textsf{translated $a$ units up}


f(x)-a \implies f(x) \: \textsf{translated $a$ units down}

Given absolute value function:


f(x)=|x|

To translate the given function 2 units to the right, subtract 2 from the x-value:


\implies f(x-2)=|x-2|

Then to translate the given function 10 units up, add 10 to the function:


\implies f(x-2)+10=|x-2|+10

Therefore, the function that translates the function f(x) = |x| to the right 2 units and up 10 units is:


\large\boxedx-2

User Aleksikallio
by
3.4k points