Question

Which frequency would be the fourth harmonic in a series for a closed pipe resonator if the findamental is 256 hz?

Answer 1

1792 Hz

Step-by-step explanation:

Answer 2

The frequency of the nth-harmonic of a closed pipe resonator is given by

`f_n = n f_1`
where
`f_1` is the fundamental frequency.

For the pipe in our problem, the fundamental frequency is
`f_1 = 256 Hz`, so the 4th harmonic (n=4) will be

`f_4 = 4 \cdot 256 Hz = 1024 Hz`