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David is standing 5000 feet away from the base of a cell phone tower. The angel of elevation from his eyes to the top of the tower is 78 degrees . If David’s eyes are 6 feet above the ground how y’all is the tower?

1 Answer

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To solve this proble you must apply the proccedure shown below:

1. You have that:

- David is standing 5000 feet away from the base of a cell phone tower. and the angel of elevation from his eyes to the top of the tower is 78 degrees.

- David’s eyes are 6 feet.

2. Therefore, you have:

Tanα=opposite/adjacent
Tanα=x/5000
x=(5000)(Tan(78°))
x=23,523.15 feet

3. Then, you have that the height of the tower is:

h=6 feet+23,523.15 feet
h=23,529.15 feet

The answer is:23,529.15 feet
User Jwodder
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