Question

How many terms must be added in an arithmetic sequence whose first term is 1818 and whose common difference is 44 to obtain a sum of 40184018​?

Answer 1

`T_n = a_1 + d(n - 1)`

When a = 18, d = 4, find the nth sequence:


`T_n = 18 + 4(n - 1)`


`T_n = 18 + 4n - 4`


`T_n = 14 + 4n`

When the nth term is 4018, find the value of n:


`14 + 4n = 4018`


`4n = 4018 - 14`


`4n = 4004`


`n = 1001`

Answer: 1001 term must be added to obtain the sum of 4018.