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Find the volume of the solid obtained by rotating the region bounded by y = 8 x 2 , x = 1 , and y = 0 , about the x -axis.

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A cross-section is a disc with radius
8x^2


V = \int_0^1 A(x)\, dx = \int_0^1 \pi\left(8x^2\right)^2 dx = \int_0^1 64 \pi x^4 = \left[(64\pi)/(5) x^5\right]_0^1 \\ \\ = (64\pi)/(5)
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