Question

A 1.5 v battery moves 9000 c of charge around a circuit. part a by how much does the chemical energy of the battery decrease

Answer 1

In moving a charge through potential difference, work done can be calculated as follows:

`W=-q* V`

Here, q is charge and V is potential difference.

(a) According to law of conservation of energy, chemical energy of the battery will be equal to work done, thus,

`E=-q* V`

Putting the values,

`E=-(9000 C)* (1.5 V)=-13500 CV`

Since, 1J=CV

Thus, the amount of chemical energy decreases will be 13500 J.

Answer 2

potential difference is energy per coloumb of charge so energy = vq

energy = 1.5 * 9000 = 13500 J