Question

A 12 v battery is connected across two parallel metal plates separated by 0.30 cm. find the magnitude of the electric field.

Answer 1

The electric field between two parallel metal plates is given by

`E= (V)/(d)`
where
E is the electric field
V is the voltage across the two plates
d is the separation between the two plates.

In our problem, the voltage is
`V=12 V` while the separation between the plates is
`d=0.30 cm=0.003 m`, therefore the magnitude of the electric field is

`E= (V)/(d)= (12 V)/(0.003 m)=4000 V/m`