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Find the volumes of the solids obtained by rotating the region bounded by the curves y = x and y = x^2 about the following lines.

(a) The x-axis
(b) The y-axis
(c) y = 2

User Ross Allen
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1 Answer

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(a) A cross-section is a washer with inner radius
x^2 and outer radius
x.


V = \int_0^1 \pi\left[(x)^2 - (x^2)^2\right]dx = \int_0^1 \pi(x^2 - x^4) dx = \pi \left[ (1)/(3)x^3 - (1)/(5)x^5\right]_0^1 \\ \\ = \pi \left[(1)/(3) - (1)/(5)\right] = (2)/(15)\pi

(b)A cross-section is a washer with inner radius
y and outer radius
√(y).


V = \int_0^1 \pi \left[ \left( √(y) \right)^2 - y^2 \right]dy = \int_0^1 \pi(y - y^2)dy = \pi \left[ (1)/(2)y^2 - (1)/(3)y^3\right]_0^1 \\ = \pi \left[ (1)/(2) - (1)/(3) \right] = (\pi)/(6)

(c) A cross-section is a washer with inner radius
2-x and outer radius
2 - x^2


V = \int_0^1 \pi\left[ (2-x^2)^2 - (2-x)^2\right] = \int_0^1 \pi (x^4 - 5x^2 + 4x) dx \\ \\ = \pi \left[ (1)/(5)x^5 - (5)/(3)x^3 + 2x^2 \right]_0^1 = \pi\left[ (1)/(5) - (5)/(3) + 2\right] = (8)/(15)\pi
User Chenghwa
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