Question

A sample of nitrogen gas, n2, is collected in a100 ml container at a pressure of 688 mm hg and a temperature of 565 °c. how many grams of nitrogen gas are present in this sample?

Answer 1

Answer: The mass of nitrogen gas present in the given sample is 0.037 g

Step-by-step explanation:

To calculate the number of moles, we use the equation given by ideal gas equation:

`PV=nRT`

Or,

`PV=(m)/(M)RT`

where,

P = Pressure of the gas = 688 mmHg

V = Volume of gas = 100 mL = 0.1 L (Conversion factor: 1 L = 1000 mL)

m = Mass of nitrogen gas = ?

M = Molar mass of nitrogen gas = 28 g/mol

R = Gas constant =
`62.3637\text{ L.mmHg }mol^(-1)K^(-1)`

T = Temperature of the gas =
`565^oC=[565+273]=838K`

Putting values in above equation, we get:

`688mmHg* 0.1L=(m)/(28g/mol)* 62.3637\text{L. mmHg }mol^(-1)K^(-1)* 838K\\\\m=0.037g`

Hence, the mass of nitrogen gas present in the given sample is 0.037 g