Question

What is the distance between the points (2, 10) and (-6, 4) on the coordinate plane

Answer 1

take the √(-1-3)^2+(3-(-4))^2

Which should give you √65 or about 8.062

Answer 2

The distance is 10 units

To find the distance, we can follow the distance formula:

√(x2 – x1)^2 + (y2 –y1)^2

We just need to substitute the values. In this case, the order the points are listed matters. If (2, 10) is the first point and (–6, 4) is the second, then 2 is x1 (the first x value), 10 is y1 (the first y value), –6 is x2 (the second x value), and 4 is y2 (the second y value).

So, now we replace to get: √(–6 – 2)^2 + (4 – 10)^2

Then we can calculate. First, the parentheses. –6 – 2 = –8, and 4 – 10 = –6
This gets us to √(–8)^2 + (–6)^2

Next, the exponents. (–8)^2 = 64 and (–6)^2 = 36. Now we're at √64 + 36

After this, we find the sum of the two values. 64 + 36 = 100, so we end up with √100

Finally, we find √100 √100 = 10, so the distance is 10 units