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X+ 3/4 ≥ -1/3
Can I get help with this I need the work and answer.

User Schrom
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Solving this inequality is similar to solving a regular equation. The only thing you need to worry about with inequalities is that when you are dividing or multiplying by a negative number, you must flip the inequality sign. You won't have to worry about that here!

You are told x + 3/4 ≥ -1/3. Isolate the x by subtracting 3/4 from both sides. To subtract fractions, find a common denominator on both fractions, subtract the numerators, put the difference over the common denominator, and simplify if needed. The common denominator between
(3)/(4) and
- (1)/(3) is 12.
1) To make the denominator of
(3)/(4), 12, multiply it by 3/3 (aka 1):

(3)/(4) * (3)/(3) = (9)/(12)

2) To make the denominator of
- (1)/(3), 12, multiply it by 4/4:

- (1)/(3) * (4)/(4) = -(4)/(12)

3) Subtract the fractions to find the inequality for x:

x + (3)/(4) \geq - (1)/(3)\\ x + (9)/(12) \geq -(4)/(12)\\ x \geq -(4)/(12) - (9)/(12) \\ x \geq -(13)/(12)

You answer is x ≥ -13/12, or if you want to make -13/12 a mixed number, x ≥
-1 (1)/(12).
User Nirmal Mangal
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