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What is the 4th term in the sequence b(n)=1(-2)^n-1
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What is the 4th term in the sequence b(n)=1(-2)^n-1

User Jabran Saeed
by
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1 Answer

1 vote

b(n)=1(-2)^n-1

When n = 4,

b(4)=1(-2)^4-1


b(4)=16-1


b(4)=15

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b(n)=1(-2)^(n-1)

When n = 4

b(4)=1(-2)^(4-1)


b(4)=1(-2)^3


b(4)=1(-8)


b(4)=-8

User Anthony Hervy
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