Given:
Initial amount owing, P=2250
APR for first three months, i1=0.036/12=0.003 per month
APR for the remaining 9 months, i2=0.288/12=0.024 per month.
Need:
1. balance at the end of first 3 months
2. number of months at regular APR (i2).
3. balance at the end of the year
4. balance at the end of the year if interest had been at regular APR for all 12 months.
5. How much did she "save".
The question is based on the compound interest formula,
F=P(1+i)^n where
F=future outstanding balance,
P=initial balance
i=interest rate per month
n=number of months.
1. Balance at the end of three months (at special APR)
F1=P(1+i1)^n=2250(1+0.003)^3=2270.31
2. For nine months Beverly paid regular APR of 28.8%
3. Balance at the end of the year
F2=F1(1+i2)^n=2270.31(1+0.024)^9=2810.51
4. Balance at end of year if interest were 28.8% all year round
F3=2250(1+0.024)^12
=2990.76
5. Amount Beverly "saved" = F3-F2=2990.76-2810.51=180.25