Question

Graph the six terms of a finite series where a1 = −3 and r = 1.5

Answer 1

Can you please show the sets

Answer 2

Six terms of this series will be (-3), (-4.5), (-6.75), (-10.125), (-15.1875), (-22.78125)

Explanation:

We have to find the six terms of a geometric series with first term = -3 and common ratio r = 1.5

The explicit form of a geometric series is represented by

`T_(n)=a(r)^(n-1)`

`T_(1)=(-3)`

`T_(2)=(-3)(1.5)^(2-1)`

= (-3)(1.5)

= -4.5

`T_(3)=(-3)(1.5)^(3-1)`

= (-3)(1.5)²

= (-3)(2.25)

= -6.75

`T_(4)=(-3)(1.5)^(4-1)`

= (-3)(1.5)³

= -10.125

`T_(5)=(-3)(1.5)^(5-1)`

=
`(-3)(1.5)^(4)`

= (-3)(5.0625)

= -15.1875

`T_(6)=(-3)(1.5)^(6-1)`

=
`(-3)(1.5)^(5)`

= (-3)(7.59375)

= -22.78125

Therefore, Six terms of this series will be (-3), (-4.5), (-6.75), (-10.125), (-15.1875), (-22.78125)