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A frog of mass 0.25 kg hops with a speed of 2.5 m/s. what is the kinetic energy of the frog?

User Umki
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2 Answers

2 votes
KE = 1/2mv^2

so


KE = 1/2(0.25)(2.5)^2 = .78 J

User MikiBelavista
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8.8k points
2 votes

Answer:

Kinetic energy, E = 0.78 Joules

Step-by-step explanation:

Given that,

Mass of frog, m = 0.25 kg

Speed of frog, v = 2.5 m/s

We need to find the kinetic energy of the frog. It is calculated when an object is in motion. It is given by :


E=(1)/(2)mv^2


E=(1)/(2)* 0.25\ kg* (2.5\ m/s) ^2

E = 0.78 Joules

So, the kinetic energy of the frog is 0.78 Joules. Hence, this is the required solution.

User Prototype
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8.1k points