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322 l of hydrogen occupies volume of 197 l at stp. what was the initial pressure exerted on the hydrogen constant

User Anthone
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The initial pressure exerted on the hydrogen constant is caculated using the Boyles law formula
that is P1V1=P2V2
P1= ?
V1= 322 L
V2= 197 L
P2 = at STP = 760 mm hg
P1 is therefore = P2V2/V1
= 760 mmhg x 197 L/ 322 L = 464.97 mmhg

User Red Wei
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