The solubility of a gas is .55 g/l at 8.0 atm pressure. what will be the solubility of the gas at 5.0 atm partial pressure?

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asked Dec 11, 2019 82.8k views

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Kindall · Answer 1 · 2019-12-17T15:29:10+0000

Henry's law states that:

P1/C1 = P2/C2

Where P = Pressure, and C = Solubility
In this case, P1 = 8.0 atm, C1 = 0.55 g/l, P2 = 5.0 atm, C2 =??

Therefore,
C2 = (P2*C1)/P1 = (5*0.55)/8 = 0.344 g/l

The solubility of a gas is .55 g/l at 8.0 atm pressure. what will be the solubility of the gas at 5.0 atm partial pressure?

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