Question

The vertices of △JKL are J(−1, 8), K(3, 5), and L(6, −9). What are the vertices of T<4, −2>(JKL)?

Answer 1

J'=(3, 6); K'=(7, 3); L'=(10, -11)

This is a translation vector that shifts the figure 4 right and 2 down. We add 4 to each x-coordinate and subtract 2 from each y-coordinate.
J'=(-1+4, 8-2) = (3, 6)
K'=(3+4, 5-2) = (7, 3)
L'=(6+4,-9-2) = (10,-11)