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the volume of gas in a container was originally 3.24L, while at standard pressure 1.00 atm. what will the volume be if the pressure is increased to 1.20 atm?

User Aldokkani
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Hello!

To solve this problem, we will use the Boyle's Law, which describes how pressure changes when volume changes and vice-versa. The equation for this law is the following one, and we'll clear for V2:


P1*V1=P2*V2 \\ \\ V2= (P1*V1)/(P2)= (3,24 L * 1 atm)/(1,20 atm)= 2,7 L

So, the final volume after increasing the pressure would be 2,7 L. That means that volume decreases when the pressure increases

Have a nice day!
User Amos Godwin
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