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A series circuit contains a 30 Ω resistor, a 20 Ω resistor, and a 10 Ω resistor. The power supply provides 100 V to the circuit.

The current in the 10 Ω resistor, to two significant figures, is
A.

User Annakata
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2 Answers

6 votes
The correct answer is 1.7 Amps.
User DanielOfTaebl
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3 votes

Answer:

The current in the 10 ohm resistance is 1.67 A.

Step-by-step explanation:

Given that,

Voltage v = 100 V

A series circuit contains a 30 Ω resistor, a 20 Ω resistor, and a 10 Ω resistor.


R =R_(1)+R_(2)+R_(3)


R = 30+20+10


R= 60\ ohm

Using Ohm's law

The voltage of the circuit is the product of the current and resistance.


V = I* R


I =(V)/(R)


I = (100)/(60)


I = 1.67\ A

The current will be same in all resistance because all resistance in series.

Hence, The current in the 10 ohm resistance is 1.67 A.

User Force Hero
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8.5k points

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