45.0k views
1 vote
There is a 0.40-A current in resistor X when it is connected to a 2.0-V battery. A 0.25-A current is in a second resistor, Y, when it is connected to a 4-V battery. There is a 0.50-A current in a third resistor, Z, when it is connected to a 5.0-V battery. Find the resistor that has the maximum resistance and the resistor that has the least resistance.

1 Answer

4 votes
We can find the value of the resistance R of each resistor by using Ohm's law:

V=IR
where
V is the potential difference across the resistor
I is the current flowing through it

First resistor:

R_X = (V)/(I)= (2.0 V)/(0.40 A)=5 \Omega
Second resistor:

R_Y = (V)/(I)= (4 V)/(0.25 A)=16 \Omega
Third resistor:

R_Z = (V)/(I)= (5.0 V)/(0.50 A)=10 \Omega

So, the resistor with the maximum resistance is the second one (Y), while the resistor with the least resistance is the first one (X)
User Gagan
by
8.7k points

No related questions found