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For a triangle ABC, find the measure of segment AB given m∠A = 55°, m∠B = 44°, and b = 68.

User Vizjerei
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2 Answers

2 votes

Answer:

96.88

58.34

39

48.4

70.0

95

169.3

Use 500(10).x

Solve for hypotonuse

Step-by-step explanation:

User Rufus
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Using SINE LAW or Rule of SINE For triangles, states that given 2 angles and 1 side, one can compute for using below equation

a/sinA = b/sinB = c/sinC, Where a & A are opposite to each other.

Thus we have segment AB which is equal to side C, manipulating the equation we have

Given : angle a = 55, angle b = 44, Therefore angle c = 180 – (55+44) = 81 deg

(AB or Side opposite of Angle C)/sin(81 deg) = b (or segment CA/AC )/sin(44 deg)

AB = sin(81 deg) * (b = 68 / sin (44 deg))

AB = 96.68, see attached image as guide

For a triangle ABC, find the measure of segment AB given m∠A = 55°, m∠B = 44°, and-example-1
User Kritner
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