Question

Use the parabola tool to graph the quadratic function f(x)=2x2+32x+126 . Graph the parabola by first plotting its vertex and then plotting a second point on the parabola

Answer 1

Here are a bunch of CORRECT answers, your answer is somewhere in there. For the first CORRECT answer the second point is -5,-9. Don't make the same mistake I did on question 3.

Answer 2

`f(x)=2x^2+32x+126`

Graph the parabola by first plotting its vertex and then plotting a second point on the parabola.

To find x coordinate of vertex we use formula
`x =(-b)/(2a)`

From the given equation , a= 2 , b= 32, c= 126

Plug in all the values

`x =(-32)/(2*2)` = -8

Now plug in 8 for x in f(x)

`f(x)=2x^2+32x+126`

`f(-8)=2(-8)^2+32(-8)+126` = -2

So vertex is (-8,-2)

Now we make a table to get some other points for graphing. We assume x value before and after vertex. Plug in -9 and -7 for x in f(x) and find out y .

`f(x)=2x^2+32x+126`

`f(-9)=2(-9)^2+32(-9)+126` = 0

`f(-7)=2(-7)^2+32(-7)+126` = 0

x ------> y

-9 ------> 0

-8 -------> -2

-7 --------> 0

Now we graph all the points.

Graph is attached below.