Question

Please help asap

Which table shows the first four terms of the sequence described by :

f(x)= 4(2)^x

x f(x)

1 8
2 16
3 32
4 64


x f(x)

1 8
2 64
3 512
4 4069


x f(x)
1 4
2 8
3 16
4 32


x f(x)
1 4
2 6
3 8
4 10

Answer 1

a

Explanation:

Answer 2

We have the following function:
f (x) = 4 (2) ^ x
Evaluating we have:
For x = 1
f (1) = 4 (2) ^ 1 = 4 * 2 = 8
For x = 2
f (2) = 4 (2) ^ 2 = 4 * 4 = 16
For x = 3
f (3) = 4 (2) ^ 3 = 4 * 8 = 32
For x = 4
f (4) = 4 (2) ^ 4 = 4 * 2 = 64


Answer:
The correct table is:
x f(x)
1 8
2 16
3 32
4 64