Question

The correct mathematical expression for finding the molar solubility (s) of sn(oh)2 is:

Answer 1

The molar solubility (s) of Sn(OH)2 can be calculated using the expression Ksp = 4s^3, and finding s requires taking the cube root of Ksp/4.

Step-by-step explanation:

The correc for finding the molar solubility (s) of Sn(OH)2 involves setting up an equilibrium expression based on the dissociation of Sn(OH)2 in water. The solubility product (Ksp) for Sn(OH)2 can be written as Ksp = [Sn2+] [OH-]2 since each mole of Sn(OH)2 that dissolves produces one mole of Sn2+ ions and two moles of OH- ions. Therefore, we express the concentration of Sn2+ as s (molar solubility) and the concentration of OH- as 2s and the expression becomes Ksp = (s)(2s)2 = 4s3.

To find the molar solubility, you solve for s in the equation Ksp = 4s3 which would be s = 3√(Ksp/4). For a given value of Ksp, this will give the molar solubility of Sn(OH)2 in mol/L.

Answer 2

Answer is: Ksp = 4s³.
Balanced chemical reaction (dissociation) of strontium hydroxide:
Sr(OH)₂(s) → Sr²⁺(aq) + 2OH⁻(aq).
Ksp(Sr(OH)₂) = [Sr²⁺]·[OH⁻]².
[Sr²⁺] = s.
[OH⁻] = [Sr²⁺] = 2s
Ksp = (2s)² · x = 4s³.
Ksp is the solubility product constant for a solid substance dissolving in an aqueous solution.
[Sr²⁺] is equilibrium concentration of iumcations.
[OH⁻] is equilibrium concentration of hydroxide anions.