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You have 7 red, 5 blue, and 3 green MnM's left in a bag. What is the probability of randomly pulling out 2 green? (The first MnM is not replaced back into the bag because you ate it) Express answer as
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You have 7 red, 5 blue, and 3 green MnM's left in a bag. What is the probability of randomly pulling out 2 green? (The first MnM is not replaced back into the bag because you ate it) Express answer as a fraction in simplest form. Explain.

User Ivan Nosov
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Total = 7 + 5 + 3 = 15
Green = 3
Red = 7

P(two green) = (3/15)(2/14) = 1/35

P(two red) = (7/15)(6/14) = 1/5

Answer: P(two green) = 1/35 ; P(two red) = 1/5
User Salindaw
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