Register

You have 7 red, 5 blue, and 3 green MnM's left in a bag. What is the probability of randomly pulling out 2 green? (The first MnM is not replaced back into the bag because y…

You have 7 red, 5 blue, and 3 green MnM's left in a bag. What is the probability of randomly pulling out 2 green? (The first MnM is not replaced back into the bag because y…
142k views
1 vote
You have 7 red, 5 blue, and 3 green MnM's left in a bag. What is the probability of randomly pulling out 2 green? (The first MnM is not replaced back into the bag because you ate it) Express answer as a fraction in simplest form. Explain.

User Ivan Nosov
by
8.1k points

1 Answer

3 votes
Total = 7 + 5 + 3 = 15
Green = 3
Red = 7

P(two green) = (3/15)(2/14) = 1/35

P(two red) = (7/15)(6/14) = 1/5

Answer: P(two green) = 1/35 ; P(two red) = 1/5
User Salindaw
by
8.8k points
← Prev Question Next Question →

Related questions

User Amyn
asked Nov 25, 2020 20.1k views
Pablito ate all my MnMs what do I do
Amyn asked Nov 25, 2020
by Amyn
7.6k points
2 answers
3 votes
20.1k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Link Copied!