Question

Find the vertext for y=x^2+10x+16

Answer 1

`\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ \begin{array}{llcccl} y = & 1x^2& +10x& +16\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array} \qquad \left(-\cfrac{ b}{2 a}\quad ,\quad c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{10^2}{2(1)}~~,~~16-\cfrac{10^2}{4(1)} \right)\implies (-50~~,~~16-25)\implies (-50~~,~~-9)`