Question

Find the perimeter of the triangle defined by the coordinates (9, 0), (-5, 0), and (-10, 6). (Round to nearest tenth)

Answer 1

The perimeter is 41.7.

We first find the distance between each vertex using the distance formula:

`d=√((y_2-y_1)^2+(x_2-x_1)^2) \\ \\=√((0-0)^2+(-5-9)^2)=√(0^2+(-14)^2)=√(196)=14 \\ \\d=√((6-0)^2+(-10--5)^2)=√(6^2+(-5)^2)=√(36+25)=√(61) \\=7.81 \\ \\d=√((6-0)^2+(-10-9)^2)=√(6^2+(-19)^2)=√(36+361)=√(397) \\=19.92`

We now find the perimeter by adding all of the side lengths:
14+7.81+19.92 = 41.73 ≈ 41.7