Question

What is the mass of 2.4 × 1023 molecules of NO2? 12 g 1.2 × 102 g 75 g 1.1 × 1023 g 18 g

Answer 1

As we know,
1 mole of any substance contains 6.022 × 10²³ particles. And 1 mole of NO₂ (equal to 46 g) contains 6.022 × 10²³ Molecules. Hence,

6.022 × 10²³ Molecules of NO₂ = 46 g
So,
2.4 × 10²³ Molecules of NO₂ = X g

Solving for X,
X = (2.4 × 10²³ Molecules × 46 g) ÷ 6.022 × 10²³ Molecules

X = 18.33 g