Question

What is the molarity of an aqueous solution containing 40.0g of glucose in 1.5l of solution?

Answer 1

Molarity of aqueous solution = 0.14 M

Step-by-step explanation:

Molarity is defined as the number of moles of solute present in 1 L of the solution.

`M = (W)/(M* \ V\ in\ L)`

Where,

W = Mass of the solute

M = Molecular mass of the solute

V = Volume of the solution

Volume of the solution = 1.5 L

Mass of glucose = 40.0 g

Molecular mass of glucose = 180.16 g/mol

`M = (40.0)/(180.16* 1.5)`

= 0.1480 M

= 0.14 M

Answer 2

The molarity of aqueous solution containing 40.0g of glucose in 1.5 L of solution calculated as follows

molarity = moles/volume in liters

find the moles of glucose = mass /molar mass
= 40/ 180.06 = 0.222 moles
molarity is therefore = 0.222/1.5 = 0.148 M