Answer:
0 N/C
Step-by-step explanation:
Using Gauss' law ∫εE.dA = Q. where E = electric field, dA = differential area and Q = charge enclosed.
Since for r < r₀ where r₀ = radius of the sphere, Q = 0. and ∫εE.dA = ∫εEdAcos180 (since the electric field is directed radially inward opposite to the normal area vector)
∫-εEdA = 0
-εE∫dA = 0
-εEA = 0
E = 0/-εA
E = 0 N/C