Question

A wye-connected load has a voltage of 480v applied to it. What is the voltage drop across each phase

Answer 1

`Y_A=277.128 \angle 30v`

`Y_B=277.128 \angle (-150)v`

`Y_C=277.128 \angle (90)v`

Step-by-step explanation:

From the question we are told that

Voltage
`V_L_L =480v`

Generally in a case of Y_connection
`V_p_ h` is mathematical represented as

`V_p_h=(V_l_l)/(√(3)) \angle (\phi-30)v`

Generally voltage drop across phase A

`Y_A=(408)/(√(3)) \angle -(0-30)`

`Y_A=277.128 \angle 30v`

Generally voltage drop across phase B

`Y_B=277.128 \angle (-30-120)`

`Y_B=277.128 \angle (-150)v`

Generally voltage drop across phase C

`Y_C=277.128 \angle (-30+120)`

`Y_C=277.128 \angle (90)v`