Question

When the vapor pressure of water is 0.106 mmHg, determine the reaction quotient for that above equilibrium.

Answer 1

Answer is explained in the explanation section below.

Step-by-step explanation:

Note: This question is not complete and lacks necessary data to solve. However, I have found a similar question and I will be using its data to solve this question for the sake of understanding and concept.

Solution:

Equilibrium Reaction:

CaO(s) + H2O(g) -->Ca(OH)2(s)

We need to find the reaction quotient for this question:

Q =
`(1)/(P_(H20) )`

Here, only the pressure of the gaseous reactant will be used and here H20 is the only reactant which is gaseous.

And we are given that, vapor pressure of water is = 0.106 mmHg

So,

Now, we need to convert it into atm

so, 1atm = 760 mmHg

0.106 mmHg = 0.106/760 atm

0.106 mmHg = 1.394 x
`10^(-4)` atm

Plugging in the values in the equation, we get:

Q =
`(1)/(P_(H20) )`

Q =
`(1)/(1.394 . 10^(-4) )`

Q = 7173.60
`atm^(-1)`