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Line JK passes through points j(-4, -5) and k(-6,3) If The Equations of the line is written in slooe intercept form y=mx+b what is the value of b?

User Sujin
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1 Answer

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The slope is (3-(-5))/(-6-(-4)) = 8/-2 = -4.
The point-slope equation is
.. y = -4(x +4) -5
.. y = -4x -21

b = -21
Line JK passes through points j(-4, -5) and k(-6,3) If The Equations of the line is-example-1
User Jace Cotton
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