Question

Given that two tangent lines are constructed from the shared point A outside a circle with the center O and points of tangency B and C, what is the measure of ∠OAB if ∠OAC measures 30°?

Answer 1

OAC =30

Explanation:

Given that for a circle there are two tangents at points of contacts B and C meet at A

The centre of the circle is O.

By tangents theorem for circles, OAB and OAC are congruent

Hence angle OAB = angle OAC

Angle OAB is given to be 30 degrees

Hence angle OAC is equal to 30 degrees

Answer 2

∠OAB = ∠OAC

∠OAB = 30°