Question

At a distance r1 from a point charge, the magnitude of the electric field created by the charge is 300 N/C. At a distance r2 from the charge, the field has a magnitude of 160 N/C. Find the ratio r2/r1.

Answer 1

the ratio of r₂/r₁ is 1.37.

Step-by-step explanation:

Given;

magnitude of electric field strength at a distance r₁, E₁ = 300 N/C

magnitude of electric field strength at a distance r₂, E₂ = 160 N/C

Electric field strength is given as;

`E = (kQ)/(r^2) \\\\E_1r_1^2 = E_2r_2 ^2\\\\(E_1)/(E_2) = (r_2^2)/(r_1^2) \\\\(E_1)/(E_2) =( (r_2)/(r_1))^2\\\\\sqrt{(E_1)/(E_2) } = (r_2)/(r_1)\\\\(r_2)/(r_1) = \sqrt{(300)/(160) }\\\\(r_2)/(r_1) =1.37`

Therefore, the ratio of r₂/r₁ is 1.37.