Balance Chemical equation is as follow,
Ca₃(PO₄)₂ + 3 H₂SO₄ → 3 CaSO₄ + 2 H₃PO₄
According to eq.
310 g (1 mole) of Ca₃(PO₄)₂ produces = 408.42 g (3 mole) of CaSO₄
So,
15.4 g of Ca₃(PO₄)₂ will produce = X g of CaSO₄
Solving for X,
X = (15.4 g × 408.42 g) ÷ 310 g
X = 20.28 g of CaSO₄