What is the value of x, if the volume of the cone is 12pi m^3

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asked Dec 19, 2019 190k views

2 Answers

Jonnnnnnnnnie · Answer 1 · 2019-12-25T18:21:47+0000

we know that

[volume of the cone]=[area of the base]*h/3
h=3*[volume of the cone]/[area of the base]

[area of the base]=pi*r²-----> pi*3²----> 9pi m²
volume of the cone=12pi m³

h=3*[12pi]/[9pi]----> 4 m

the answer is
4 m

What is the value of x, if the volume of the cone is 12pi m^3

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