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Simplify x^3-125/2x-10

User Sreekuttan
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We \ first, \ simplify \ (125)/(2) \\ \\ \left[\begin{array}{ccc}((x^3)-( (125)/(2)*x))-10 \end{array}\right] \\ \\ \boxed{\boxed{x^3= (x^3)/(1) = (x^3*2)/(2) }} \\ \\ \\ \boxed{ (x^3*2-(125x))/(2) = (2x^3-125x)/(2) } \\ \\ \\ ((2^3-125x)/(2) -10 \\ \\ pulling \ out \ like \ factors : \\ \\ 2x^3 - 125x = x * (2x^2 - 125) \\ \\ Factoring: \ 2x^2 - 125

Here's how!


Proof : \ (A+B) * (A-B) =\\ A2 - AB + BA - B2 =\\ A2 - AB + AB - B2 = \\ A2 - B2\\

Therefore . . .


\boxed{ (x*(2x^2-125)-(10*2))/(2) = (2x^3-125x-20)/(2) }

The factors would then be the following:


( Leading \ Coefficient : 1,2)

(Trailing Constant) : 1 ,2 ,4 ,5 ,10 ,20

By then, understanding on how we have got in our terms, such as the like terms, and also how we have understanded the coefficient's, we would then have our answer clear below.


\leadsto \ Your \ answer: \boxed{\bf{ (2x^3-125x-20)/(2) }}
User KoleS
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