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Which strategies can be used to solve this problem? A county fair plans to have 24 pigs in its pig exhibit area. Eight pigs can fit in a large circular pen. The rest of the pigs will be put into square pens that can each fit 2 pigs. What is the fewest number of square pens that will be needed so each pig is in a pen? .

A.
Work backward. Find the number of square pens by dividing 24 by 2. Then what is left over goes into the circular pen.


B.
Use logical reasoning.
Subtract 2 pigs 7 times. The number of pigs left will be the number of pigs in the square pens.


C.
Translate into an equation.
(24 – 8) ÷ 2 = p


D.
Model the problem. Use 24 objects to represent the pigs. Move 8 objects into one group. Then put the remaining objects into groups of 2. Then count the groups of 2 to find the number of square pens.

User Jose
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1 Answer

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the most logical ones would be C and D spends on ur grade I would say C though
User Willy Keatinge
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