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Christina rolls a number cube twice.What is the probability she rolls a prime number and then an odd number?

User WaltiD
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The probability is 3/6 (1/2) as there are 3 prime numbers on a dice (2,3,5) and also 3 odd numbers on a dice (1,3,5)
User Hooman Askari
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Christina rolls a number cube twice.

Number of outcomes in a cube = 1,2,3,4,5,6 = 6 outcomes

Prime numbers = 2,3,5 = 3 outcomes

Odd numbers = 1,3,5 = 3 outcomes

probability that she rolls a prime number =
(outcome of a prime number )/(total number of outcomes) =
(3)/(6) = (1)/(2)

probability that she rolls a odd number =
(outcome of a odd number )/(total number of outcomes) =
(3)/(6) = (1)/(2)

probability (a prime number and then an odd number) =


(1)/(2) *
(1)/(2) =
(1)/(4)

User SimpLE MAn
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