Question

A ball made out of a special material is inflated such that its diameter changes from 14 inches to 18 inches. What is the approximate change in the volume of the ball?

Answer 1

The volume of the ball is:
V = (4/3) * (pi) * (r ^ 3)
Where r is the radius.
We have then:
diameter 14 inches:
V1 = (4/3) * (pi) * ((14/2) ^ 3)
V1 = 1436.75504 in ^ 3
diameter 18 inches:
V2 = (4/3) * (pi) * ((18/2) ^ 3)
V2 = 3053.628059 in ^ 3
The volume change is:
V = V2-V1
V = 3053.628059 - 1436.75504
V = 1616.873019 in ^ 3
Answer:
The approximate change in the volume of the ball is:
V = 1616.9 in ^ 3