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What is the focal length f of this lens in air (index of refraction for air is nair=1)? express your answer in centimeters to two significant figures or as a fraction?

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The complete question is:
"A convex-convex lens has radii of curvature with magnitudes of |R₁| = 10 cm and |R₂| = 15 cm. The lens is made of glass with an index of refraction n_glass = 1.5. We will employ the convention that R₁ refers to the radius of curvature of the surface through which light will enter the lens, and R₂ refers to the radius of curvature of the surface from which light will exit the lens."

The focal length can be calculated by the formula:

(1)/(f) = ( (n_(glass) )/( n_(air) ) - 1)( (1)/( R_(1) ) + (1)/( R_(2) ) )
= (1.5 - 1)(1/10 + 1/15)
= 1/12

Therefore, the focal length of the lens is f = 12 cm.
User Justin Pavatte
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