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25 votes
Factor completely.

a^3x-a^2x

1 Answer

8 votes

Answer:
xa^2\left(a-1\right)

Explanation:


\mathrm{Apply\:exponent\:rule}:\quad \:a^(b+c)=a^ba^c


xa^3=xa^2a


=xa^2a-xa^2


\mathrm{Factor\:out\:common\:term\:}xa^2


=xa^2\left(a-1\right)

Final Answer:
xa^2\left(a-1\right)

User NShiny
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