Question

A loop should output 1 to n. If n is 5, the output is 12345. What should XXX and YYY be? Choices are in the form XXX / YYY. cin >> n; for (XXX; i++) { cout << YYY; }

Answer 1

To output numbers from 1 to n in a for loop, initialize the loop with 'i = 1' (XXX) and increment until 'i <= n'. Print 'i' (YYY) for each loop iteration to produce the sequence 12345 if n is 5.

Step-by-step explanation:

The student is asking for help with a for loop in a programming context, most likely within the C++ language. The goal is to output numbers from 1 to n, and if n is 5, the output should be 12345. To achieve this, the for loop needs to be set up properly. The initialization part of the loop (XXX) should start with i at 1, and it should continue as long as i is less than or equal to n. Therefore, the correct XXX is i = 1. The loop should output the current value of i each iteration, so YYY should be i. The complete loop would look like this:

cin >> n;
for (int i = 1; i <= n; i++) {
cout << i;
}

So, for the given question, XXX should be i = 1 and YYY should be i.

Answer 2

`i = 0; i < n / i + 1`

Step-by-step explanation:

Given that:

a loop output 1 → n

if n = 5

output = 12345

n = scnr.nextInt();

for
`(XXX; i++)`

{

System.out.printIn(YYY);

}

XXX / YYY is
`i = 0; i < n / i + 1`