Question

PLEASE HELP!!! I NEED THE ANSWER SOON :)

Answer 1

`y=2x \\ewline y= x^(2) -3`

Substitue 2x for y in the second equation:


`2x= x^(2) -3`

Rearrange to
`a x^(2) +bx+c=0` form:


`x^(2) -2x-3=0`

Factor:


`(x-3)(x+1)=0`

Zeros are
`x=3` and
`x=-1`

To find y-coordinates of pts of intersection, plug these x-values into first equation to get
`y=-2` and
`y=6`